0.6x^2+4x-35=0

Solution for 0.6x^2+4x-35=0 equation:

0.6x^2+4x-35=0

a = 0.6; b = 4; c = -35;
Δ = b2-4ac
Δ = 42-4·0.6·(-35)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-10}{2*0.6}=\frac{-14}{1.2}
=-11+0.8/1.2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+10}{2*0.6}=\frac{6}{1.2}
=5
$